What is the solution for (4x+ye^{y/x})dx-xe^{y/x}dy=0 ?

The solution for (4x+ye^{y/x})dx-xe^{y/x}dy=0 is y=ln(4ln(x)+c_{1})x

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(4x+ye^{y/x})dx-xe^{y/x}dy=0

(4 x + y e^{\frac{y}{x}}) d x - x e^{\frac{y}{x}} d y = 0

y = ln (4 ln (x) + c_{1}) x

Solution steps

(4 x + y e^{\frac{y}{x}}) d x - x e^{\frac{y}{x}} d y = 0

Solve using substitution:

y = ln (4 ln (x) + c_{1}) x

y = ln (4 ln (x) + c_{1}) x

(e^{- x}) (x^{2} - x)

\int \frac{( x ^{2} )}{9 + x ^{2}} d x

\frac{1}{( 1 - x )}

3 x + 7

What is the solution for (4x+ye^{y/x})dx-xe^{y/x}dy=0 ?
The solution for (4x+ye^{y/x})dx-xe^{y/x}dy=0 is y=ln(4ln(x)+c_{1})x