What is the integral of (e^x-26^x) ?

The integral of (e^x-26^x) is e^x-(26^x)/(ln(26))+C

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integral of (e^x-26^x)

\int (e^{x} - 2 6^{x}) d x

e^{x} - \frac{2 6 ^{x}}{ln ( 26 )} + C

Solution steps

\int e^{x} - 2 6^{x} d x

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int e^{x} d x - \int 2 6^{x} d x

\int e^{x} d x = e^{x}

\int 2 6^{x} d x = \frac{2 6 ^{x}}{ln ( 26 )}

= e^{x} - \frac{2 6 ^{x}}{ln ( 26 )}

Add a constant to the solution

= e^{x} - \frac{2 6 ^{x}}{ln ( 26 )} + C

3 25 - x^{2}

\frac{d}{d x} (9 x^{\frac{7}{2}})

f (x) = \frac{x ^{3} + 2 x ^{2} + x + 2}{x + 2}

\int e^{- 6 x} tan (e^{- 6 x}) d x

y^{^{'}} - (\frac{2 x}{1 + x ^{2}}) y = 0

What is the integral of (e^x-26^x) ?
The integral of (e^x-26^x) is e^x-(26^x)/(ln(26))+C