What is derivative of f(x)=(2t-1)(3t-4)^{-1} ?

The answer to derivative of f(x)=(2t-1)(3t-4)^{-1} is (dt)/(dx)=0

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derivative of f(x)=(2t-1)(3t-4)^{-1}

derivative of

f (x) = (2 t - 1) (3 t - 4)^{- 1}

\frac{d t}{d x} = 0

Solution steps

f (x) = (2 t - 1) (3 t - 4)^{- 1}

Treat

t

t (x)

Differentiate both sides:

0 = - \frac{5 \frac{d t}{d x}}{( 3 t - 4 ) ^{2}}

Isolate

\frac{d t}{d x} : \frac{d t}{d x} = 0

\frac{d t}{d x} = 0

2^{4 x} + 4 x^{2}

\int \frac{1}{4 ^{2 x}} d x

ln (ln (4 s))

\frac{\partial}{\partial x} (x^{3} + 2 x y + y^{2})

\frac{d}{d x} (0.015 + x)

What is derivative of f(x)=(2t-1)(3t-4)^{-1} ?
The answer to derivative of f(x)=(2t-1)(3t-4)^{-1} is (dt)/(dx)=0