What is the integral of (sin(ln(8x)))/x ?

The integral of (sin(ln(8x)))/x is -cos(ln(8x))+C

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integral of (sin(ln(8x)))/x

\int \frac{sin ( ln ( 8 x ) )}{x} d x

- cos (ln (8 x)) + C

Solution steps

\int \frac{sin ( ln ( 8 x ) )}{x} d x

Apply u-substitution

: \int \frac{sin ( ln ( u ) )}{u} d u

= \int \frac{sin ( ln ( u ) )}{u} d u

Apply u-substitution

: \int sin (v) d v

= \int sin (v) d v

Use the common integral:

\int sin (v) d v = - cos (v)

= - cos (v)

Substitute back

= - cos (ln (8 x))

Add a constant to the solution

= - cos (ln (8 x)) + C

\frac{\partial}{\partial x} (2 e^{- 2 x} + \frac{1}{3} e^{x})

\int_{0}^{0.07} 600 x d x

\int_{0}^{\frac{π}{6}} tan (2 x) d x

y + x^{2} + y^{2} - x y^{^{'}} = 0

f (x) = 2 e^{x} cos (x)

What is the integral of (sin(ln(8x)))/x ?
The integral of (sin(ln(8x)))/x is -cos(ln(8x))+C