What is the integral of ([sin(x)]^2x+[cos(x)]^2x) ?

The integral of ([sin(x)]^2x+[cos(x)]^2x) is (x^2)/2+C

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integral of ([sin(x)]^2x+[cos(x)]^2x)

\int ([sin (x)]^{2} x + [cos (x)]^{2} x) d x

\frac{x ^{2}}{2} + C

Solution steps

\int [sin (x)]^{2} x + [cos (x)]^{2} x d x

Rewrite using trig identities

= \int x d x

Apply the Power Rule

: \frac{x ^{2}}{2}

= \frac{x ^{2}}{2}

Add a constant to the solution

= \frac{x ^{2}}{2} + C

\int \frac{( 1 + x ) ^{3}}{x} d x

\int_{1}^{\infty} \frac{1}{4 + x ^{2}} d x

\frac{d}{d x} ((2 x - 1)^{3} (3 x + 2)^{4})

\frac{d y}{d x} = tan (x)

n = 0 \sum \infty x^{(1 + n)}

What is the integral of ([sin(x)]^2x+[cos(x)]^2x) ?
The integral of ([sin(x)]^2x+[cos(x)]^2x) is (x^2)/2+C