What is the solution for (dy)/(dx)+4tan(4x)y=3cos(4x) ?

The solution for (dy)/(dx)+4tan(4x)y=3cos(4x) is y=(3x)/(sec(4x))+(c_{1})/(sec(4x))

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(dy)/(dx)+4tan(4x)y=3cos(4x)

\frac{d y}{d x} + 4 tan (4 x) y = 3 cos (4 x)

y = \frac{3 x}{sec ( 4 x )} + \frac{c _{1}}{sec ( 4 x )}

Solution steps

\frac{d y}{d x} + 4 tan (4 x) y = 3 cos (4 x)

Solve linear ODE:

y = \frac{3 x}{sec ( 4 x )} + \frac{c _{1}}{sec ( 4 x )}

y = \frac{3 x}{sec ( 4 x )} + \frac{c _{1}}{sec ( 4 x )}

(0, 1), (4, - 5)

\frac{1 + x ^{2}}{( 1 - x ^{2} ) ^{2}}

\frac{d}{d x} (ln (4 - x))

\frac{d}{d x} (\frac{2 - x}{x + 4})

f (t) = 5 t - 8 t^{2}

What is the solution for (dy)/(dx)+4tan(4x)y=3cos(4x) ?
The solution for (dy)/(dx)+4tan(4x)y=3cos(4x) is y=(3x)/(sec(4x))+(c_{1})/(sec(4x))