What is the solution for derivative of y+x+x+y+1=0 ?

The solution for derivative of y+x+x+y+1=0 is y=-x-1+(c_{1})/(e^x)

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derivative of y+x+x+y+1=0

\frac{d}{d x} (y + x) + x + y + 1 = 0

y = - x - 1 + \frac{c _{1}}{e ^{x}}

Solution steps

\frac{d}{d x} (y + x) + x + y + 1 = 0

Solve linear ODE:

y = - x - 1 + \frac{c _{1}}{e ^{x}}

y = - x - 1 + \frac{c _{1}}{e ^{x}}

\int \frac{1}{- x ^{2} + 2 x + 8} d x

\frac{\partial}{\partial x} (2 x y + y cos (x))

e^{8 x} - e^{2 x}, x = 1

y = x - 6, y^{2} = 2 x + 108

What is the solution for derivative of y+x+x+y+1=0 ?
The solution for derivative of y+x+x+y+1=0 is y=-x-1+(c_{1})/(e^x)