What is the derivative of e^{-bt} ?

The derivative of e^{-bt} is -be^{-bt}

What is the first derivative of e^{-bt} ?

The first derivative of e^{-bt} is -be^{-bt}

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derivative of

e^{- b t}

- b e^{- b t}

Solution steps

\frac{d}{d t} (e^{- b t})

Apply the chain rule:

e^{- b t} \frac{d}{d t} (- b t)

= e^{- b t} \frac{d}{d t} (- b t)

\frac{d}{d t} (- b t) = - b

= e^{- b t} (- b)

Simplify

= - b e^{- b t}

x \to - 2 - lim (\frac{1 - x}{x ^{3} + 8})

\frac{d}{d x} ((1 + i)^{x})

\frac{\partial}{\partial x} ((4 x + 8) ln (6 x y))

\frac{d}{d x} (4 e^{- 3 x})

\frac{d}{d x} (- cos (2 x) - 2 sin (2 x) (1 - x))

What is the derivative of e^{-bt} ?
The derivative of e^{-bt} is -be^{-bt}
What is the first derivative of e^{-bt} ?
The first derivative of e^{-bt} is -be^{-bt}