What is the integral from 0 to pi/3 of 1sec^2(x) ?

The integral from 0 to pi/3 of 1sec^2(x) is square root of 3

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integral from 0 to pi/3 of 1sec^2(x)

\int_{0}^{\frac{π}{3}} 1 sec^{2} (x) d x

3

Decimal Notation

1.73205 \dots

Solution steps

\int_{0}^{\frac{π}{3}} 1 \cdot sec^{2} (x) d x

Simplify

= \int_{0}^{\frac{π}{3}} sec^{2} (x) d x

Use the common integral:

\int sec^{2} (x) d x = tan (x)

= [tan (x)]_{0}^{\frac{π}{3}}

Compute the boundaries:

3

= 3

\int \frac{5}{x ln ( 4 x )} d x

\frac{d}{d x} (- 4 e^{- 4 x})

\frac{d}{d x} (7 x - 8)

n = 0 \sum \infty (400) (0.1)^{n}

\frac{d y}{d x} = \frac{x ^{2} + 2}{3 y ^{2}}

What is the integral from 0 to pi/3 of 1sec^2(x) ?
The integral from 0 to pi/3 of 1sec^2(x) is square root of 3