What is (\partial)/(\partial y)(y+xy) ?

The answer to (\partial)/(\partial y)(y+xy) is 1+x

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(\partial)/(\partial y)(y+xy)

\frac{\partial}{\partial y} (y + x y)

1 + x

Solution steps

\frac{\partial}{\partial y} (y + x y)

Treat

x

as a constant

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{\partial}{\partial y} (y) + \frac{\partial}{\partial y} (x y)

\frac{\partial}{\partial y} (y) = 1

\frac{\partial}{\partial y} (x y) = x

= 1 + x

x \to - 4 lim (\frac{x ^{2} + 3 x - 4}{x + 4})

- x^{2} + 1

(x^{3} - 4 x) (5 x^{2} + 2 x)

\frac{d}{d x} (e^{x^{4} + 7 x})

\frac{\partial}{\partial x} (7 + x ln (x y - 9))

What is (\partial)/(\partial y)(y+xy) ?
The answer to (\partial)/(\partial y)(y+xy) is 1+x