What is the integral of \sqrt[4]{cot(x)}csc^2(x) ?

The integral of \sqrt[4]{cot(x)}csc^2(x) is -4/5 cot^{5/4}(x)+C

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

integral of \sqrt[4]{cot(x)}csc^2(x)

- \frac{4}{5} cot^{\frac{5}{4}} (x) + C

Solution steps

Apply u-substitution

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

Apply the Power Rule

: \frac{4}{5} u^{\frac{5}{4}}

= - \frac{4}{5} u^{\frac{5}{4}}

Substitute back

u = cot (x)

= - \frac{4}{5} cot^{\frac{5}{4}} (x)

Add a constant to the solution

= - \frac{4}{5} cot^{\frac{5}{4}} (x) + C

x \to 0 lim (\frac{x}{∣ x ∣} sin (x))

\frac{\partial}{\partial r} (2 π r^{2} + 2 π r h)

\frac{d}{d x} (2 tan^{2} (x))

\frac{d}{d x} (6 sin (x) cos (x))

\int_{0}^{2} \frac{y}{9 - y ^{2}} d y

What is the integral of \sqrt[4]{cot(x)}csc^2(x) ?
The integral of \sqrt[4]{cot(x)}csc^2(x) is -4/5 cot^{5/4}(x)+C