What is the integral of (3-x^2)/x ?

The integral of (3-x^2)/x is 3ln|x|-(x^2)/2+C

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integral of (3-x^2)/x

\int \frac{3 - x ^{2}}{x} d x

3 ln ∣ x ∣ - \frac{x ^{2}}{2} + C

Solution steps

\int \frac{3 - x ^{2}}{x} d x

Expand

\frac{3 - x ^{2}}{x} : \frac{3}{x} - x

= \int \frac{3}{x} - x d x

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int \frac{3}{x} d x - \int x d x

\int \frac{3}{x} d x = 3 ln ∣ x ∣

\int x d x = \frac{x ^{2}}{2}

= 3 ln ∣ x ∣ - \frac{x ^{2}}{2}

Add a constant to the solution

= 3 ln ∣ x ∣ - \frac{x ^{2}}{2} + C

8 csc (x) + 2

f (x) = x - 2 sin (x)

n = 0 \sum \infty \frac{1}{2 ^{n} - 1}

\frac{\partial}{\partial x} (z - e^{x y})

ln (\frac{( e ^{x} + 1 )}{e ^{x} - 1})

What is the integral of (3-x^2)/x ?
The integral of (3-x^2)/x is 3ln|x|-(x^2)/2+C