What is the derivative of f(x)= 1/(x^2) ?

The derivative of f(x)= 1/(x^2) is -2/(x^3)

What is the first derivative of f(x)= 1/(x^2) ?

The first derivative of f(x)= 1/(x^2) is -2/(x^3)

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derivative of

f (x) = \frac{1}{x ^{2}}

- \frac{2}{x ^{3}}

Solution steps

\frac{d}{d x} (\frac{1}{x ^{2}})

Apply exponent rule:

\frac{1}{a} = a^{- 1}

= \frac{d}{d x} (x^{- 2})

Apply the Power Rule:

\frac{d}{d x} (x^{a}) = a \cdot x^{a - 1}

= - 2 x^{- 2 - 1}

Simplify

- 2 x^{- 2 - 1} : - \frac{2}{x ^{3}}

= - \frac{2}{x ^{3}}

\frac{d}{d x} (x^{3} - 3 x^{2} + 4)

\int \frac{1}{csc ( 5 x ) cos ( 5 x )} d x

\frac{d}{d x} (e^{2 x + y})

\int \frac{- 5 x - 41}{x ^{2} + x - 12} d x

\int (x^{4} - 5 e^{- 2 x}) d x

What is the derivative of f(x)= 1/(x^2) ?
The derivative of f(x)= 1/(x^2) is -2/(x^3)
What is the first derivative of f(x)= 1/(x^2) ?
The first derivative of f(x)= 1/(x^2) is -2/(x^3)