What is the derivative of x^3-3x^2+4 ?

The derivative of x^3-3x^2+4 is 3x^2-6x

What is the first derivative of x^3-3x^2+4 ?

The first derivative of x^3-3x^2+4 is 3x^2-6x

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\frac{d}{d x} (x^{3} - 3 x^{2} + 4)

3 x^{2} - 6 x

Solution steps

\frac{d}{d x} (x^{3} - 3 x^{2} + 4)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (x^{3}) - \frac{d}{d x} (3 x^{2}) + \frac{d}{d x} (4)

\frac{d}{d x} (x^{3}) = 3 x^{2}

\frac{d}{d x} (3 x^{2}) = 6 x

\frac{d}{d x} (4) = 0

= 3 x^{2} - 6 x + 0

Simplify

= 3 x^{2} - 6 x

\int \frac{1}{csc ( 5 x ) cos ( 5 x )} d x

\frac{d}{d x} (e^{2 x + y})

\int \frac{- 5 x - 41}{x ^{2} + x - 12} d x

\int (x^{4} - 5 e^{- 2 x}) d x

\frac{d}{d x} ((x^{2} + 4 x - 5)^{3})

What is the derivative of x^3-3x^2+4 ?
The derivative of x^3-3x^2+4 is 3x^2-6x
What is the first derivative of x^3-3x^2+4 ?
The first derivative of x^3-3x^2+4 is 3x^2-6x