What is (\partial)/(\partial y)(2/y) ?

The answer to (\partial)/(\partial y)(2/y) is -2/(y^2)

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(\partial)/(\partial y)(2/y)

\frac{\partial}{\partial y} (\frac{2}{y})

- \frac{2}{y ^{2}}

Solution steps

\frac{\partial}{\partial y} (\frac{2}{y})

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= 2 \frac{\partial}{\partial y} (\frac{1}{y})

Apply exponent rule:

\frac{1}{a} = a^{- 1}

= 2 \frac{\partial}{\partial y} (y^{- 1})

Apply the Power Rule:

\frac{d}{d x} (x^{a}) = a \cdot x^{a - 1}

= 2 (- 1 \cdot y^{- 1 - 1})

Simplify

2 (- 1 \cdot y^{- 1 - 1}) : - \frac{2}{y ^{2}}

= - \frac{2}{y ^{2}}

x^{2} y^{^{'}} - 4 x y = sin (3 x) x^{6}

f (x) = 2 sec (x) tan (x)

\int \frac{( 6 + e ^{x} ) ^{2}}{e ^{x}} d x

f (x) = e^{x} + ln (x + 1)

\frac{1}{2 x ^{\frac{1}{2}}} + \frac{1}{4 x ^{\frac{3}{4}}}

What is (\partial)/(\partial y)(2/y) ?
The answer to (\partial)/(\partial y)(2/y) is -2/(y^2)