What is the derivative of 4sin(3x) ?

The derivative of 4sin(3x) is 12cos(3x)

What is the first derivative of 4sin(3x) ?

The first derivative of 4sin(3x) is 12cos(3x)

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derivative of

4 sin (3 x)

12 cos (3 x)

Solution steps

\frac{d}{d x} (4 sin (3 x))

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= 4 \frac{d}{d x} (sin (3 x))

Apply the chain rule:

cos (3 x) \frac{d}{d x} (3 x)

= cos (3 x) \frac{d}{d x} (3 x)

\frac{d}{d x} (3 x) = 3

= 4 cos (3 x) \cdot 3

Simplify

= 12 cos (3 x)

\int \frac{2 - x}{4 x ^{2} + 4 x - 3} d x

\frac{d y}{d x} + x^{2} (3 y - 2) = 0

\int x^{6} d x

\frac{d}{d x} (\frac{( 1 - x )}{1 + x})

\frac{d}{d x} (9 - 6 x)

What is the derivative of 4sin(3x) ?
The derivative of 4sin(3x) is 12cos(3x)
What is the first derivative of 4sin(3x) ?
The first derivative of 4sin(3x) is 12cos(3x)