What is the derivative of y=ln(x-4) ?

The derivative of y=ln(x-4) is 1/(x-4)

What is the first derivative of y=ln(x-4) ?

The first derivative of y=ln(x-4) is 1/(x-4)

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derivative of

y = ln (x - 4)

\frac{1}{x - 4}

Solution steps

\frac{d}{d x} (ln (x - 4))

Apply the chain rule:

\frac{1}{x - 4} \frac{d}{d x} (x - 4)

= \frac{1}{x - 4} \frac{d}{d x} (x - 4)

\frac{d}{d x} (x - 4) = 1

= \frac{1}{x - 4} \cdot 1

Simplify

= \frac{1}{x - 4}

\int π (\frac{9}{x ^{2} + 9})^{2} d x

4 x y \frac{d y}{d x} = 1

- 5 e^{2 t}

((x - 4)^{2})^{^{'}}

n = 1 \sum \infty n! (x - 1)^{n}

What is the derivative of y=ln(x-4) ?
The derivative of y=ln(x-4) is 1/(x-4)
What is the first derivative of y=ln(x-4) ?
The first derivative of y=ln(x-4) is 1/(x-4)