What is the derivative of y=2x^2sqrt(25-x^2) ?

The derivative of y=2x^2sqrt(25-x^2) is (2(-3x^3+50x))/(sqrt(25-x^2))

What is the first derivative of y=2x^2sqrt(25-x^2) ?

The first derivative of y=2x^2sqrt(25-x^2) is (2(-3x^3+50x))/(sqrt(25-x^2))

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derivative of

y = 2 x^{2} 25 - x^{2}

\frac{2 ( - 3 x ^{3} + 50 x )}{25 - x ^{2}}

Solution steps

\frac{d}{d x} (2 x^{2} 25 - x^{2})

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= 2 \frac{d}{d x} (x^{2} 25 - x^{2})

Apply the Product Rule:

(f \cdot g)^{'} = f^{'} \cdot g + f \cdot g^{'}

f = x^{2}, g = 25 - x^{2}

= 2 (\frac{d}{d x} (x^{2}) 25 - x^{2} + \frac{d}{d x} (25 - x^{2}) x^{2})

\frac{d}{d x} (x^{2}) = 2 x

\frac{d}{d x} (25 - x^{2}) = - \frac{x}{25 - x ^{2}}

= 2 (2 x 25 - x^{2} + (- \frac{x}{25 - x ^{2}}) x^{2})

Simplify

2 (2 x 25 - x^{2} + (- \frac{x}{25 - x ^{2}}) x^{2}) : \frac{2 ( - 3 x ^{3} + 50 x )}{25 - x ^{2}}

= \frac{2 ( - 3 x ^{3} + 50 x )}{25 - x ^{2}}

y^{^{'}} = x y - y

\int \frac{2 x}{x ^{2} + 2} d x

f (x) = \frac{3}{4} x^{8}

\frac{3}{sin ( 2 x )}

2 y^{^{''}} + 5 y^{^{'}} - 3 y = 0, y (0) = 3, y^{^{'}} (0) = 19

What is the derivative of y=2x^2sqrt(25-x^2) ?
The derivative of y=2x^2sqrt(25-x^2) is (2(-3x^3+50x))/(sqrt(25-x^2))
What is the first derivative of y=2x^2sqrt(25-x^2) ?
The first derivative of y=2x^2sqrt(25-x^2) is (2(-3x^3+50x))/(sqrt(25-x^2))