What is the derivative of 3/(sin(2x)) ?

The derivative of 3/(sin(2x)) is -6cot(2x)csc(2x)

What is the first derivative of 3/(sin(2x)) ?

The first derivative of 3/(sin(2x)) is -6cot(2x)csc(2x)

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derivative of

\frac{3}{sin ( 2 x )}

- 6 cot (2 x) csc (2 x)

Solution steps

\frac{d}{d x} (\frac{3}{sin ( 2 x )})

Simplify

\frac{3}{sin ( 2 x )} : 3 csc (2 x)

= \frac{d}{d x} (3 csc (2 x))

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= 3 \frac{d}{d x} (csc (2 x))

Apply the chain rule:

- cot (2 x) csc (2 x) \frac{d}{d x} (2 x)

= - cot (2 x) csc (2 x) \frac{d}{d x} (2 x)

\frac{d}{d x} (2 x) = 2

= 3 (- cot (2 x) csc (2 x) \cdot 2)

Simplify

= - 6 cot (2 x) csc (2 x)

2 y^{^{''}} + 5 y^{^{'}} - 3 y = 0, y (0) = 3, y^{^{'}} (0) = 19

f (x) = \frac{7}{8 t ^{4}}

f (x) = 2 x^{3} - x^{2} + 2, at x = 1

\int ln (t) d t

\frac{d}{d x} (ln (2 - 3 x))

What is the derivative of 3/(sin(2x)) ?
The derivative of 3/(sin(2x)) is -6cot(2x)csc(2x)
What is the first derivative of 3/(sin(2x)) ?
The first derivative of 3/(sin(2x)) is -6cot(2x)csc(2x)