What is the integral of e^{-x}sin(5x) ?

The integral of e^{-x}sin(5x) is -(5e^{-x}cos(5x))/(26)-(e^{-x}sin(5x))/(26)+C

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integral of e^{-x}sin(5x)

\int e^{- x} sin (5 x) d x

- \frac{5 e ^{- x} cos ( 5 x )}{26} - \frac{e ^{- x} sin ( 5 x )}{26} + C

Solution steps

\int e^{- x} sin (5 x) d x

Apply Integration By Parts

: - \frac{1}{5} e^{- x} cos (5 x) - \int \frac{1}{5} e^{- x} cos (5 x) d x

= - \frac{1}{5} e^{- x} cos (5 x) - \int \frac{1}{5} e^{- x} cos (5 x) d x

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= - \frac{1}{5} e^{- x} cos (5 x) - \frac{1}{5} \cdot \int e^{- x} cos (5 x) d x

Apply Integration By Parts

: \frac{1}{5} e^{- x} sin (5 x) - \int - \frac{1}{5} e^{- x} sin (5 x) d x

= - \frac{1}{5} e^{- x} cos (5 x) - \frac{1}{5} (\frac{1}{5} e^{- x} sin (5 x) - \int - \frac{1}{5} e^{- x} sin (5 x) d x)

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= - \frac{1}{5} e^{- x} cos (5 x) - \frac{1}{5} (\frac{1}{5} e^{- x} sin (5 x) - (- \frac{1}{5} \cdot \int e^{- x} sin (5 x) d x))

Therefore

\int e^{- x} sin (5 x) d x = - \frac{1}{5} e^{- x} cos (5 x) - \frac{1}{5} (\frac{1}{5} e^{- x} sin (5 x) - (- \frac{1}{5} \cdot \int e^{- x} sin (5 x) d x))

Isolate

\int e^{- x} sin (5 x) d x

= - \frac{5 e ^{- x} cos ( 5 x )}{26} - \frac{e ^{- x} sin ( 5 x )}{26}

Add a constant to the solution

= - \frac{5 e ^{- x} cos ( 5 x )}{26} - \frac{e ^{- x} sin ( 5 x )}{26} + C

y = \frac{x}{x + 5}, (4, \frac{2}{9})

y^{^{'}} + y^{2} sin (t) = 0

\int e^{- 10 t} d t

\frac{\partial}{\partial y} (x^{2} + y^{3})

\frac{d}{d x} (\frac{1 - 4 x}{5 + x})

What is the integral of e^{-x}sin(5x) ?
The integral of e^{-x}sin(5x) is -(5e^{-x}cos(5x))/(26)-(e^{-x}sin(5x))/(26)+C