What is the derivative of (x^4+7x^2-9)^5 ?

The derivative of (x^4+7x^2-9)^5 is 5(x^4+7x^2-9)^4(4x^3+14x)

What is the first derivative of (x^4+7x^2-9)^5 ?

The first derivative of (x^4+7x^2-9)^5 is 5(x^4+7x^2-9)^4(4x^3+14x)

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derivative of

(x^{4} + 7 x^{2} - 9)^{5}

5 (x^{4} + 7 x^{2} - 9)^{4} (4 x^{3} + 14 x)

Solution steps

\frac{d}{d x} ((x^{4} + 7 x^{2} - 9)^{5})

Apply the chain rule:

5 (x^{4} + 7 x^{2} - 9)^{4} \frac{d}{d x} (x^{4} + 7 x^{2} - 9)

= 5 (x^{4} + 7 x^{2} - 9)^{4} \frac{d}{d x} (x^{4} + 7 x^{2} - 9)

\frac{d}{d x} (x^{4} + 7 x^{2} - 9) = 4 x^{3} + 14 x

= 5 (x^{4} + 7 x^{2} - 9)^{4} (4 x^{3} + 14 x)

\int (\frac{x + 1}{x - 1}) d x

f (x) = e^{x}, at x = ln (13)

f (x) = e^{x} (8 + 3 x + 5 x^{2}), at x = 0

\frac{d}{d x} (x^{3} e^{- 4 x})

\frac{d y}{d x} + y - 4 cos (x) = 0

What is the derivative of (x^4+7x^2-9)^5 ?
The derivative of (x^4+7x^2-9)^5 is 5(x^4+7x^2-9)^4(4x^3+14x)
What is the first derivative of (x^4+7x^2-9)^5 ?
The first derivative of (x^4+7x^2-9)^5 is 5(x^4+7x^2-9)^4(4x^3+14x)