What is the integral of 8x^3-6x^2+10x-9 ?

The integral of 8x^3-6x^2+10x-9 is 2x^4-2x^3+5x^2-9x+C

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

integral of 8x^3-6x^2+10x-9

\int 8 x^{3} - 6 x^{2} + 10 x - 9 d x

2 x^{4} - 2 x^{3} + 5 x^{2} - 9 x + C

Solution steps

\int 8 x^{3} - 6 x^{2} + 10 x - 9 d x

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int 8 x^{3} d x - \int 6 x^{2} d x + \int 10 x d x - \int 9 d x

\int 8 x^{3} d x = 2 x^{4}

\int 6 x^{2} d x = 2 x^{3}

\int 10 x d x = 5 x^{2}

\int 9 d x = 9 x

= 2 x^{4} - 2 x^{3} + 5 x^{2} - 9 x

Add a constant to the solution

= 2 x^{4} - 2 x^{3} + 5 x^{2} - 9 x + C

\frac{d y}{d x} = x + y

\frac{d}{d x} (\frac{sec ( x )}{2 + sec ( x )})

3 (x^{2} + y^{2}) d x + x d y - y d x = 0

5 x^{2} - 4 x y + 3 y^{3} = 993

x \to 6 lim (12)

What is the integral of 8x^3-6x^2+10x-9 ?
The integral of 8x^3-6x^2+10x-9 is 2x^4-2x^3+5x^2-9x+C