What is the solution for 3(x^2+y^2)dx+xdy-ydx=0 ?

The solution for 3(x^2+y^2)dx+xdy-ydx=0 is y=tan(-3x+c_{1})x

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3(x^2+y^2)dx+xdy-ydx=0

3 (x^{2} + y^{2}) d x + x d y - y d x = 0

y = tan (- 3 x + c_{1}) x

Solution steps

3 (x^{2} + y^{2}) d x + x d y - y d x = 0

Solve using substitution:

y = tan (- 3 x + c_{1}) x

y = tan (- 3 x + c_{1}) x

5 x^{2} - 4 x y + 3 y^{3} = 993

x \to 6 lim (12)

f (x) = 3 x - 2 x^{2}

\frac{d}{d x} (25 I n (x^{2}) - x^{2})

n = 1 \sum \infty \frac{2 n + 1}{n}

What is the solution for 3(x^2+y^2)dx+xdy-ydx=0 ?
The solution for 3(x^2+y^2)dx+xdy-ydx=0 is y=tan(-3x+c_{1})x