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Popular >

area x=9y^3,x=23y^2

Solution

area

x = 9 y^{3}, x = 23 y^{2}

Solution

\frac{279841}{8748}

+1

Solution steps

Isolate

y

for

Isolate

y

for

x = 23 y^{2} : y = \frac{x}{23}, y = - \frac{x}{23}

f_{2} (x) = \frac{x}{23}

To find the intersection points solve

f_{i} (x) = f_{j} (x)

\frac{x}{23} = - \frac{x}{23} : x = 0

= \int_{0}^{\frac{12167}{81}} ∣ f_{1} (x) - f_{2} (x) ∣ d x

= \frac{279841}{8748}

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Frequently Asked Questions (FAQ)

What is area x=9y^3,x=23y^2 ?
The answer to area x=9y^3,x=23y^2 is 279841/8748