What is the solution for y^{''}-2y^'+y=0,y(0)=-1,y^'(0)=-2 ?

The solution for y^{''}-2y^'+y=0,y(0)=-1,y^'(0)=-2 is y=-e^t-e^tt

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y^{''}-2y^'+y=0,y(0)=-1,y^'(0)=-2

y^{^{''}} - 2 y^{^{'}} + y = 0, y (0) = - 1, y^{^{'}} (0) = - 2

y = - e^{t} - e^{t} t

Solution steps

y^{''} (t) - 2 y^{'} (t) + y = 0

Solve linear ODE:

y = - e^{t} - e^{t} t

y = - e^{t} - e^{t} t

c y^{- 3}

f (x) = ln (x + 5)

\frac{70}{x}

\int sin (30 x) d x

n = 1 \sum \infty \frac{1}{n + 3}

What is the solution for y^{''}-2y^'+y=0,y(0)=-1,y^'(0)=-2 ?
The solution for y^{''}-2y^'+y=0,y(0)=-1,y^'(0)=-2 is y=-e^t-e^tt