What is (\partial)/(\partial x)(3cos(xy)) ?

The answer to (\partial)/(\partial x)(3cos(xy)) is -3ysin(xy)

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(\partial)/(\partial x)(3cos(xy))

\frac{\partial}{\partial x} (3 cos (x y))

- 3 y sin (x y)

Solution steps

\frac{\partial}{\partial x} (3 cos (x y))

Treat

y

as a constant

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= 3 \frac{\partial}{\partial x} (cos (x y))

Apply the chain rule:

- sin (x y) \frac{\partial}{\partial x} (x y)

= - sin (x y) \frac{\partial}{\partial x} (x y)

\frac{\partial}{\partial x} (x y) = y

= 3 (- sin (x y) y)

Simplify

= - 3 y sin (x y)

\frac{1}{( 1 - 3 \cdot x ^{3} ) ^{3}}

f (x) = 10 x, (10, 10)

\int \frac{x - 1}{x ^{2} - 4 x + 5} d x

\frac{d y}{d x} + y = - 1, y (0) = 1

2 x - 3

What is (\partial)/(\partial x)(3cos(xy)) ?
The answer to (\partial)/(\partial x)(3cos(xy)) is -3ysin(xy)