What is (\partial ^2)/(\partial y^2)(x^2+y^2) ?

The answer to (\partial ^2)/(\partial y^2)(x^2+y^2) is 2

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(\partial ^2)/(\partial y^2)(x^2+y^2)

\frac{\partial ^{2}}{\partial y ^{2}} (x^{2} + y^{2})

2

Solution steps

\frac{\partial ^{2}}{\partial y ^{2}} (x^{2} + y^{2})

\frac{\partial}{\partial y} (x^{2} + y^{2}) = 2 y

= \frac{\partial}{\partial y} (2 y)

\frac{\partial}{\partial y} (2 y) = 2

= 2

y^{^{'}} + 9 x^{- 1} y = x^{7}, y (1) = 8

\int (5 x - 3)^{2} (2 x - 1) d x

x \to 0 lim (x ln (1 + \frac{1}{x}))

\frac{- 3 x + 12}{2 6 - x}

f (x) = (tan (\frac{1}{x}))^{s e c (\frac{1}{x})}

What is (\partial ^2)/(\partial y^2)(x^2+y^2) ?
The answer to (\partial ^2)/(\partial y^2)(x^2+y^2) is 2