What is the derivative of sqrt(x^4+y^4) ?

The derivative of sqrt(x^4+y^4) is (2x^3)/(sqrt(x^4+y^4))

What is the first derivative of sqrt(x^4+y^4) ?

The first derivative of sqrt(x^4+y^4) is (2x^3)/(sqrt(x^4+y^4))

Popular >

derivative of

x^{4} + y^{4}

\frac{2 x ^{3}}{x ^{4} + y ^{4}}

Solution steps

\frac{d}{d x} (x^{4} + y^{4})

Treat

y

as a constant

Apply the chain rule:

\frac{1}{2 x ^{4} + y ^{4}} \frac{d}{d x} (x^{4} + y^{4})

= \frac{1}{2 x ^{4} + y ^{4}} \frac{d}{d x} (x^{4} + y^{4})

\frac{d}{d x} (x^{4} + y^{4}) = 4 x^{3}

= \frac{1}{2 x ^{4} + y ^{4}} \cdot 4 x^{3}

Simplify

\frac{1}{2 x ^{4} + y ^{4}} \cdot 4 x^{3} : \frac{2 x ^{3}}{x ^{4} + y ^{4}}

= \frac{2 x ^{3}}{x ^{4} + y ^{4}}

\int \frac{sin ( x )}{4} d x

f (x) = 14 - x, at x = 5

\frac{\partial}{\partial x} (\frac{1}{x} + \frac{1}{y})

\frac{d}{d x} ((4 - x^{\frac{2}{3}})^{\frac{3}{2}})

e^{- 3 x^{2}}

What is the derivative of sqrt(x^4+y^4) ?
The derivative of sqrt(x^4+y^4) is (2x^3)/(sqrt(x^4+y^4))
What is the first derivative of sqrt(x^4+y^4) ?
The first derivative of sqrt(x^4+y^4) is (2x^3)/(sqrt(x^4+y^4))