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Popular >

area y=8x,y=4x^2

Solution

area

y = 8 x, y = 4 x^{2}

Solution

\frac{16}{3}

+1

Decimal Notation

5.33333 \dots

Solution steps

Apply the area formula:

\int_{0}^{2} 8 x - 4 x^{2} d x

Solve

\int_{0}^{2} 8 x - 4 x^{2} d x : \frac{16}{3}

The area is:

= \frac{16}{3}

Popular Examples

(\partial)/(\partial y)(2e^xln(y))

\frac{\partial}{\partial y} (2 e^{x} ln (y))

(\partial)/(\partial x)(4xy+yz+3xz-32)

\frac{\partial}{\partial x} (4 x y + yz + 3 x z - 32)

derivative of x^6e^{2x^3}

\frac{d}{d x} (x^{6} e^{2 x^{3}})

maclaurin (1+x^2)^{(-3)/2}maclaurin

(1 + x^{2})^{\frac{- 3}{2}}

y^'=((3y^2+9))/(2xy)

y^{^{'}} = \frac{( 3 y ^{2} + 9 )}{2 x y}

Frequently Asked Questions (FAQ)

What is area y=8x,y=4x^2 ?
The answer to area y=8x,y=4x^2 is 16/3