What is (\partial)/(\partial y)(2e^xln(y)) ?

The answer to (\partial)/(\partial y)(2e^xln(y)) is (2e^x)/y

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(\partial)/(\partial y)(2e^xln(y))

\frac{\partial}{\partial y} (2 e^{x} ln (y))

\frac{2 e ^{x}}{y}

Solution steps

\frac{\partial}{\partial y} (2 e^{x} ln (y))

Treat

x

as a constant

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= 2 e^{x} \frac{\partial}{\partial y} (ln (y))

Apply the common derivative:

\frac{\partial}{\partial y} (ln (y)) = \frac{1}{y}

= 2 e^{x} \frac{1}{y}

Simplify

2 e^{x} \frac{1}{y} : \frac{2 e ^{x}}{y}

= \frac{2 e ^{x}}{y}

\frac{\partial}{\partial x} (4 x y + yz + 3 x z - 32)

\frac{d}{d x} (x^{6} e^{2 x^{3}})

(1 + x^{2})^{\frac{- 3}{2}}

y^{^{'}} = \frac{( 3 y ^{2} + 9 )}{2 x y}

n = 1 \sum \infty \frac{1}{2 + n}

What is (\partial)/(\partial y)(2e^xln(y)) ?
The answer to (\partial)/(\partial y)(2e^xln(y)) is (2e^x)/y