What is the derivative of (x^2-x/x) ?

The derivative of (x^2-x/x) is 1

What is the first derivative of (x^2-x/x) ?

The first derivative of (x^2-x/x) is 1

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\frac{d}{d x} (\frac{x ^{2} - x}{x})

1

Solution steps

\frac{d}{d x} (\frac{x ^{2} - x}{x})

Simplify

\frac{x ^{2} - x}{x} : x - 1

= \frac{d}{d x} (x - 1)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d x}{d x} - \frac{d}{d x} (1)

\frac{d x}{d x} = 1

\frac{d}{d x} (1) = 0

= 1 - 0

Simplify

= 1

\frac{d y}{d x} + 4 y = - x

\int e^{2 x} (2) d x

y^{^{'}} = y^{\frac{2}{3}}

\int \frac{4}{- 3 x} d x

\frac{d}{d x} (I n^{2})

What is the derivative of (x^2-x/x) ?
The derivative of (x^2-x/x) is 1
What is the first derivative of (x^2-x/x) ?
The first derivative of (x^2-x/x) is 1