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Popular >

(tdu)/(dt)=t^2+3u

Solution

\frac{t d u}{d t} = t^{2} + 3 u

Solution

u = - t^{2} + c_{1} t^{3}

Solution steps

\frac{t d u}{d t} = t^{2} + 3 u

Solve linear ODE:

u = - t^{2} + c_{1} t^{3}

u = - t^{2} + c_{1} t^{3}

Popular Examples

(\partial)/(\partial x)(-6x^3+10y^2-4xy)

\frac{\partial}{\partial x} (- 6 x^{3} + 10 y^{2} - 4 x y)

integral of (-3x+4)e^{-x}

\int (- 3 x + 4) e^{- x} d x

(dy)/(dx)=((2y+1))/((x+1))

\frac{d y}{d x} = \frac{( 2 y + 1 )}{( x + 1 )}

x^{^{'}} x - 5 x = 25

derivative of f(x)= x/(x+7)derivative of

f (x) = \frac{x}{x + 7}

Frequently Asked Questions (FAQ)

What is the solution for (tdu)/(dt)=t^2+3u ?
The solution for (tdu)/(dt)=t^2+3u is u=-t^2+c_{1}t^3