What is derivative of f(x)=(5t^2-2t+1)^{3/2} ?

The answer to derivative of f(x)=(5t^2-2t+1)^{3/2} is (dt)/(dx)=0

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derivative of f(x)=(5t^2-2t+1)^{3/2}

derivative of

f (x) = (5 t^{2} - 2 t + 1)^{\frac{3}{2}}

\frac{d t}{d x} = 0

Solution steps

f (x) = (5 t^{2} - 2 t + 1)^{\frac{3}{2}}

Treat

t

t (x)

Differentiate both sides:

0 = 3 \frac{d t}{d x} (5 t - 1) (5 t^{2} - 2 t + 1)^{\frac{1}{2}}

Isolate

\frac{d t}{d x} : \frac{d t}{d x} = 0

\frac{d t}{d x} = 0

\int_{1}^{2} \frac{1}{( x + 1 ) ^{2}} d x

f (x) = ∣ x - 1 ∣

\frac{\partial}{\partial y} (ln (x + 3 y))

\int \frac{x - 2}{x ^{2} - x} d x

\int_{0}^{2} 2^{x} d x

What is derivative of f(x)=(5t^2-2t+1)^{3/2} ?
The answer to derivative of f(x)=(5t^2-2t+1)^{3/2} is (dt)/(dx)=0