What is (\partial)/(\partial x)(e^xcos(y)+yz) ?

The answer to (\partial)/(\partial x)(e^xcos(y)+yz) is e^xcos(y)

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(\partial)/(\partial x)(e^xcos(y)+yz)

\frac{\partial}{\partial x} (e^{x} cos (y) + yz)

e^{x} cos (y)

Solution steps

\frac{\partial}{\partial x} (e^{x} cos (y) + yz)

Treat

y, z

as constants

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{\partial}{\partial x} (e^{x} cos (y)) + \frac{\partial}{\partial x} (yz)

\frac{\partial}{\partial x} (e^{x} cos (y)) = cos (y) e^{x}

\frac{\partial}{\partial x} (yz) = 0

= cos (y) e^{x} + 0

Simplify

= e^{x} cos (y)

\frac{d}{d x} (\frac{x ( x + 10 )}{( x + 5 ) ^{2}})

x \to 1 lim ((2 x - 3) \cdot (x + 1))

y^{^{''}} + 1.5 y^{^{'}} - y = 12 x^{2} + 6 x^{3} - x^{4}

\frac{d}{d x} (e^{m t} \cdot sin (n t))

f (x) = 3 cos (2 ln (x))

What is (\partial)/(\partial x)(e^xcos(y)+yz) ?
The answer to (\partial)/(\partial x)(e^xcos(y)+yz) is e^xcos(y)