What is the derivative of (3+x^4)^{4/5} ?

The derivative of (3+x^4)^{4/5} is (16x^3)/(5(3+x^4)^{1/5)}

What is the first derivative of (3+x^4)^{4/5} ?

The first derivative of (3+x^4)^{4/5} is (16x^3)/(5(3+x^4)^{1/5)}

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derivative of

(3 + x^{4})^{\frac{4}{5}}

\frac{16 x ^{3}}{5 ( 3 + x ^{4} ) ^{\frac{1}{5}}}

Solution steps

\frac{d}{d x} ((3 + x^{4})^{\frac{4}{5}})

Apply the chain rule:

\frac{4}{5 ( 3 + x ^{4} ) ^{\frac{1}{5}}} \frac{d}{d x} (3 + x^{4})

= \frac{4}{5 ( 3 + x ^{4} ) ^{\frac{1}{5}}} \frac{d}{d x} (3 + x^{4})

\frac{d}{d x} (3 + x^{4}) = 4 x^{3}

= \frac{4}{5 ( 3 + x ^{4} ) ^{\frac{1}{5}}} \cdot 4 x^{3}

Simplify

\frac{4}{5 ( 3 + x ^{4} ) ^{\frac{1}{5}}} \cdot 4 x^{3} : \frac{16 x ^{3}}{5 ( 3 + x ^{4} ) ^{\frac{1}{5}}}

= \frac{16 x ^{3}}{5 ( 3 + x ^{4} ) ^{\frac{1}{5}}}

x \to 0 + lim (\frac{10}{x ^{2}})

f (x) = 17 e^{x} - e x^{e}

f (x) = \frac{x}{x + 2}

\frac{d y}{d t} = 9 t^{2}

x \to - 2 lim (3 x^{2} - 3 x - 8)

What is the derivative of (3+x^4)^{4/5} ?
The derivative of (3+x^4)^{4/5} is (16x^3)/(5(3+x^4)^{1/5)}
What is the first derivative of (3+x^4)^{4/5} ?
The first derivative of (3+x^4)^{4/5} is (16x^3)/(5(3+x^4)^{1/5)}