What is the limit as x approaches-1 of (2x)/(x+1) ?

The limit as x approaches-1 of (2x)/(x+1) is diverges

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limit as x approaches-1 of (2x)/(x+1)

x \to - 1 lim (\frac{2 x}{x + 1})

diverges

Solution steps

x \to - 1 lim (\frac{2 x}{x + 1})

x \to a - lim f (x) \neq = x \to a + lim f (x)

then the limit does not exist

x \to - 1 + lim (\frac{2 x}{x + 1}) = - \infty

x \to - 1 - lim (\frac{2 x}{x + 1}) = \infty

= diverges

n = 1 \sum \infty \frac{3}{n ^{4}}

\frac{d}{d x} (\frac{1}{arctan ( x )})

h \to 0 lim (\frac{( 1 + h ) ^{2} - 1}{h})

x \to 1 lim (1 + 6 x^{2})

y = \frac{- 8 x}{x ^{2} + 1}, (1, - 4)

What is the limit as x approaches-1 of (2x)/(x+1) ?
The limit as x approaches-1 of (2x)/(x+1) is diverges