What is the integral of 4/369 x^3 ?

The integral of 4/369 x^3 is (x^4)/(369)+C

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integral of 4/369 x^3

\int \frac{4}{369} x^{3} d x

\frac{x ^{4}}{369} + C

Solution steps

\int \frac{4}{369} x^{3} d x

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= \frac{4}{369} \cdot \int x^{3} d x

Apply the Power Rule

: \frac{x ^{4}}{4}

= \frac{4}{369} \cdot \frac{x ^{4}}{4}

Simplify

\frac{4}{369} \cdot \frac{x ^{4}}{4} : \frac{x ^{4}}{369}

= \frac{x ^{4}}{369}

Add a constant to the solution

= \frac{x ^{4}}{369} + C

x \to 1 lim (3 x^{2} + 4)

y = x^{2} - 8, y = 8

\frac{d}{d x} (sin (π^{2}))

(e^{- \frac{x}{2}})^{^{'}}

y^{^{'}} - y = 1, y (0) = 1