What is the limit as x approaches 1 of sqrt(3x^2+4) ?

The limit as x approaches 1 of sqrt(3x^2+4) is square root of 7

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

limit as x approaches 1 of sqrt(3x^2+4)

x \to 1 lim (3 x^{2} + 4)

7

Decimal Notation

2.64575 \dots

Solution steps

x \to 1 lim (3 x^{2} + 4)

Plug in the value

x = 1

= 3 \cdot 1^{2} + 4

Simplify

= 7

y = x^{2} - 8, y = 8

\frac{d}{d x} (sin (π^{2}))

(e^{- \frac{x}{2}})^{^{'}}

y^{^{'}} - y = 1, y (0) = 1

\int sin^{3} (18 x) cos^{3} (18 x) d x

What is the limit as x approaches 1 of sqrt(3x^2+4) ?
The limit as x approaches 1 of sqrt(3x^2+4) is square root of 7