What is the derivative of sqrt(6+x^2) ?

The derivative of sqrt(6+x^2) is x/(sqrt(6+x^2))

What is the first derivative of sqrt(6+x^2) ?

The first derivative of sqrt(6+x^2) is x/(sqrt(6+x^2))

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\frac{d}{d x} (6 + x^{2})

\frac{x}{6 + x ^{2}}

Solution steps

\frac{d}{d x} (6 + x^{2})

Apply the chain rule:

\frac{1}{2 6 + x ^{2}} \frac{d}{d x} (6 + x^{2})

= \frac{1}{2 6 + x ^{2}} \frac{d}{d x} (6 + x^{2})

\frac{d}{d x} (6 + x^{2}) = 2 x

= \frac{1}{2 6 + x ^{2}} \cdot 2 x

Simplify

\frac{1}{2 6 + x ^{2}} \cdot 2 x : \frac{x}{6 + x ^{2}}

= \frac{x}{6 + x ^{2}}

\int 2 x + 1 d x

\int 3^{x} sin (x) d x

\frac{\partial}{\partial y} (y cos (x ln (y)))

\int_{0}^{2} 1 + 3 x^{2} d x

6 x^{- 3}, at x = 5

What is the derivative of sqrt(6+x^2) ?
The derivative of sqrt(6+x^2) is x/(sqrt(6+x^2))
What is the first derivative of sqrt(6+x^2) ?
The first derivative of sqrt(6+x^2) is x/(sqrt(6+x^2))