en

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

y^'=ln(x)

Solution

y^{^{'}} = ln (x)

Solution

y = x ln (x) - x + c_{1}

Solution steps

y^{'} (x) = ln (x)

If

f^{^{'}} (x) = g (x)

then

f (x) = \int g (x) d x

y = \int ln (x) d x

\int ln (x) d x = x ln (x) - x + c_{1}

y = x ln (x) - x + c_{1}

Popular Examples

laplacetransform f(t)=(1+e^{4t})^2 laplace transform

f (t) = (1 + e^{4 t})^{2}

integral of (3x+1)/(x(x+1)^2)

\int \frac{3 x + 1}{x ( x + 1 ) ^{2}} d x

laplacetransform e^{-2t-5}laplace transform

e^{- 2 t - 5}

(\partial)/(\partial x)(y*ln(x))

\frac{\partial}{\partial x} (y \cdot ln (x))

derivative of se^{-sx{y}(s,x})

\frac{d}{d x} (s e^{- s x y (s, x)})

Frequently Asked Questions (FAQ)

What is the solution for y^'=ln(x) ?
The solution for y^'=ln(x) is y=xln(x)-x+c_{1}