What is the solution for 2z(3z+1)dw+(1-2w)dz=0 ?

The solution for 2z(3z+1)dw+(1-2w)dz=0 is w=(c_{1}z)/(2(3z+1))+1/2

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2z(3z+1)dw+(1-2w)dz=0

2 z (3 z + 1) d w + (1 - 2 w) d z = 0

w = \frac{c _{1} z}{2 ( 3 z + 1 )} + \frac{1}{2}

Solution steps

2 z (3 z + 1) d w + (1 - 2 w) d z = 0

Solve separable ODE:

w = \frac{c _{1} z}{2 ( 3 z + 1 )} + \frac{1}{2}

w = \frac{c _{1} z}{2 ( 3 z + 1 )} + \frac{1}{2}

\frac{\partial}{\partial y} (e^{x y z^{3}} y z^{3})

\int x (a - b x^{2}) d x

f (x) = 2 x^{2} + x - 2, at x = 4

\int \frac{- 1600 x}{25 - x ^{2}} d x

\int \frac{1}{x 8 x + 81} d x

What is the solution for 2z(3z+1)dw+(1-2w)dz=0 ?
The solution for 2z(3z+1)dw+(1-2w)dz=0 is w=(c_{1}z)/(2(3z+1))+1/2