What is the derivative of (x^2-25/(x+5)) ?

The derivative of (x^2-25/(x+5)) is 1

What is the first derivative of (x^2-25/(x+5)) ?

The first derivative of (x^2-25/(x+5)) is 1

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\frac{d}{d x} (\frac{x ^{2} - 25}{x + 5})

1

Solution steps

\frac{d}{d x} (\frac{x ^{2} - 25}{x + 5})

Simplify

\frac{x ^{2} - 25}{x + 5} : x - 5

= \frac{d}{d x} (x - 5)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d x}{d x} - \frac{d}{d x} (5)

\frac{d x}{d x} = 1

\frac{d}{d x} (5) = 0

= 1 - 0

Simplify

= 1

\frac{d}{d x} (x^{4} + \frac{4}{3} x^{3} - 4 x^{2})

\int (- 3 x + 2) e^{- x} d x

x \to 0 lim (\frac{7 e ^{x}}{x ^{5}})

\int 4 x^{2} - 2 d x

x \to + 1 lim (0)

What is the derivative of (x^2-25/(x+5)) ?
The derivative of (x^2-25/(x+5)) is 1
What is the first derivative of (x^2-25/(x+5)) ?
The first derivative of (x^2-25/(x+5)) is 1