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Popular >

integral of 1/(x-4)

Solution

\int \frac{1}{x - 4} d x

Solution

ln ∣ x - 4 ∣ + C

Solution steps

\int \frac{1}{x - 4} d x

Apply u-substitution

: \int \frac{1}{u} d u

= \int \frac{1}{u} d u

Use the common integral:

\int \frac{1}{u} d u = ln (∣ u ∣)

= ln ∣ u ∣

Substitute back

u = x - 4

= ln ∣ x - 4 ∣

Add a constant to the solution

= ln ∣ x - 4 ∣ + C

Popular Examples

sum from n=8 to infinity of 1/n sin(1/n)

n = 8 \sum \infty \frac{1}{n} sin (\frac{1}{n})

y^'=(ty)/(t+1),y(4)=1

y^{^{'}} = \frac{t y}{t + 1}, y (4) = 1

integral of 1/(x\sqrt[5]{x)}

(x+y)dx+(3x+3y-4)dy=0

(x + y) d x + (3 x + 3 y - 4) d y = 0

derivative of e^{-4x^3-2x+4}

\frac{d}{d x} (e^{- 4 x^{3} - 2 x + 4})

Frequently Asked Questions (FAQ)

What is the integral of 1/(x-4) ?
The integral of 1/(x-4) is ln|x-4|+C