What is the derivative of y=ln(x^6) ?

The derivative of y=ln(x^6) is 6/x

What is the first derivative of y=ln(x^6) ?

The first derivative of y=ln(x^6) is 6/x

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derivative of

y = ln (x^{6})

\frac{6}{x}

Solution steps

\frac{d}{d x} (ln (x^{6}))

Apply the chain rule:

\frac{1}{x ^{6}} \frac{d}{d x} (x^{6})

= \frac{1}{x ^{6}} \frac{d}{d x} (x^{6})

\frac{d}{d x} (x^{6}) = 6 x^{5}

= \frac{1}{x ^{6}} \cdot 6 x^{5}

Simplify

\frac{1}{x ^{6}} \cdot 6 x^{5} : \frac{6}{x}

= \frac{6}{x}

x \to 0 lim ((e^{x} - x)^{\frac{1}{x}})

\int \frac{1 + sin ( x )}{x ^{3}} d x

\int_{0}^{9} π (x - 1)^{2} d x

y = 7 e^{x} cos (x), (0, 7)

4 t^{3} - t^{2}, t^{4} + 2 t^{2}, 1 \leq t \leq 3

What is the derivative of y=ln(x^6) ?
The derivative of y=ln(x^6) is 6/x
What is the first derivative of y=ln(x^6) ?
The first derivative of y=ln(x^6) is 6/x