What is (\partial)/(\partial x)(tan(x-y)) ?

The answer to (\partial)/(\partial x)(tan(x-y)) is sec^2(x-y)

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(\partial)/(\partial x)(tan(x-y))

\frac{\partial}{\partial x} (tan (x - y))

sec^{2} (x - y)

Solution steps

\frac{\partial}{\partial x} (tan (x - y))

Treat

y

as a constant

Apply the chain rule:

sec^{2} (x - y) \frac{\partial}{\partial x} (x - y)

= sec^{2} (x - y) \frac{\partial}{\partial x} (x - y)

\frac{\partial}{\partial x} (x - y) = 1

= sec^{2} (x - y) \cdot 1

Simplify

= sec^{2} (x - y)

\int ln (1) d x

(x^{3} + e^{y}) d y = 3 x^{2} d x

y^{^{'}} + 8 y = x e^{- 8 x}

64 - x^{2}

h \to 0 lim (- \frac{1}{x ( x + h )})

What is (\partial)/(\partial x)(tan(x-y)) ?
The answer to (\partial)/(\partial x)(tan(x-y)) is sec^2(x-y)