What is (\partial)/(\partial x)(2y+x^2+1) ?

The answer to (\partial)/(\partial x)(2y+x^2+1) is 2x

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(\partial)/(\partial x)(2y+x^2+1)

\frac{\partial}{\partial x} (2 y + x^{2} + 1)

2 x

Solution steps

\frac{\partial}{\partial x} (2 y + x^{2} + 1)

Treat

y

as a constant

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{\partial}{\partial x} (2 y) + \frac{\partial}{\partial x} (x^{2}) + \frac{\partial}{\partial x} (1)

\frac{\partial}{\partial x} (2 y) = 0

\frac{\partial}{\partial x} (x^{2}) = 2 x

\frac{\partial}{\partial x} (1) = 0

= 0 + 2 x + 0

Simplify

= 2 x

2 cos^{2} (t)

y = ln (\frac{x + 3}{x ^{2}})

\frac{d}{d x} (x^{3} 1 - x^{2})

n = 1 \sum \infty \frac{n !}{3 n ! - 1}

What is (\partial)/(\partial x)(2y+x^2+1) ?
The answer to (\partial)/(\partial x)(2y+x^2+1) is 2x