What is the derivative of \sqrt[7]{x}-7e^x ?

The derivative of \sqrt[7]{x}-7e^x is 1/(7x^{6/7)}-7e^x

What is the first derivative of \sqrt[7]{x}-7e^x ?

The first derivative of \sqrt[7]{x}-7e^x is 1/(7x^{6/7)}-7e^x

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derivative of

\frac{1}{7 x ^{\frac{6}{7}}} - 7 e^{x}

Solution steps

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

\frac{d}{d x} (7 e^{x}) = 7 e^{x}

= \frac{1}{7 x ^{\frac{6}{7}}} - 7 e^{x}

\frac{d}{d x} (x^{3} 1 - x^{2})

n = 1 \sum \infty \frac{n !}{3 n ! - 1}

y = 3 x + 1, y = 13 + 2 x - x^{2}

f (x) = 2 x + 1, at x = 1

\frac{d}{d x} (\frac{2 x + ∣ x ∣}{1 + ∣ x ∣})

What is the derivative of \sqrt[7]{x}-7e^x ?
The derivative of \sqrt[7]{x}-7e^x is 1/(7x^{6/7)}-7e^x
What is the first derivative of \sqrt[7]{x}-7e^x ?
The first derivative of \sqrt[7]{x}-7e^x is 1/(7x^{6/7)}-7e^x