What is the sum from n=1 to infinity of (n!)/(3n!-1) ?

The sum from n=1 to infinity of (n!)/(3n!-1) is diverges

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sum from n=1 to infinity of (n!)/(3n!-1)

n = 1 \sum \infty \frac{n !}{3 n ! - 1}

diverges

Solution steps

n = 1 \sum \infty \frac{n !}{3 n ! - 1}

Apply Series Divergence Test:

diverges

= diverges

y = 3 x + 1, y = 13 + 2 x - x^{2}

f (x) = 2 x + 1, at x = 1

\frac{d}{d x} (\frac{2 x + ∣ x ∣}{1 + ∣ x ∣})

\int \frac{9 x ^{2} - 8 x + 20}{x ^{3} + 4 x} d x

\frac{75 x}{x ^{2} + 100}

What is the sum from n=1 to infinity of (n!)/(3n!-1) ?
The sum from n=1 to infinity of (n!)/(3n!-1) is diverges