What is (\partial)/(\partial y)(2y^2+3x) ?

The answer to (\partial)/(\partial y)(2y^2+3x) is 4y

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(\partial)/(\partial y)(2y^2+3x)

\frac{\partial}{\partial y} (2 y^{2} + 3 x)

4 y

Solution steps

\frac{\partial}{\partial y} (2 y^{2} + 3 x)

Treat

x

as a constant

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{\partial}{\partial y} (2 y^{2}) + \frac{\partial}{\partial y} (3 x)

\frac{\partial}{\partial y} (2 y^{2}) = 4 y

\frac{\partial}{\partial y} (3 x) = 0

= 4 y + 0

Simplify

= 4 y

x \to 0 lim (\frac{3}{0})

n = 0 \sum \infty (\frac{1}{3})^{2 n}

\frac{5 x}{4 x ^{2} + 1}

\int \frac{x}{x ^{2} + 2 x + 2} d x

Y (x) = x^{3} - x^{2} - 6 x, Y (x) = 0

What is (\partial)/(\partial y)(2y^2+3x) ?
The answer to (\partial)/(\partial y)(2y^2+3x) is 4y