What is the integral of (7-3x-9x^2) ?

The integral of (7-3x-9x^2) is 7x-(3x^2)/2-3x^3+C

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integral of (7-3x-9x^2)

\int (7 - 3 x - 9 x^{2}) d x

7 x - \frac{3 x ^{2}}{2} - 3 x^{3} + C

Solution steps

\int 7 - 3 x - 9 x^{2} d x

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int 7 d x - \int 3 x d x - \int 9 x^{2} d x

\int 7 d x = 7 x

\int 3 x d x = \frac{3 x ^{2}}{2}

\int 9 x^{2} d x = 3 x^{3}

= 7 x - \frac{3 x ^{2}}{2} - 3 x^{3}

Add a constant to the solution

= 7 x - \frac{3 x ^{2}}{2} - 3 x^{3} + C

\frac{d}{d x} (\frac{2 x ^{2} + 1}{x ^{2} + 7})

\frac{d}{d x} (sin (cos (2 x)))

n = 1 \sum \infty \frac{1}{5 ^{n - 1}}

\frac{\partial}{\partial x} (cos (y - x))

x \to - 2 lim (7 x + 12)

What is the integral of (7-3x-9x^2) ?
The integral of (7-3x-9x^2) is 7x-(3x^2)/2-3x^3+C